algebra\nfind the value of y.\n1. 3y = 27\n2. 9y = 81\n3. 12y = 132\n4. 6y = 72\n5. 20y = 120\n6. 15y =…

algebra\nfind the value of y.\n1. 3y = 27\n2. 9y = 81\n3. 12y = 132\n4. 6y = 72\n5. 20y = 120\n6. 15y = 75\n7. 10y = 160\n8. 9y = 72\n9. 11y = 88\n10. 4y = 36\n11. 5y + 15 = 65\n12. 9y + 20 = 83\n13. 7y + 9 = 44\n14. 4y + 18 = 34\n15. 6y + 40 = 100\n16. 12y - 15 = 45\n17. 8y - 22 = 42\n18. 5y - 8 = 27\n19. 11y - 13 = 53\n20. 3y - 24 = 0\nworksheet 1

Answer

Explanation:

Step1: Isolate y for simple equations

For equations of the form $ay = b$, divide both sides by $a$. For example, for $3y = 27$, we have $y=\frac{27}{3}$.

Step2: Isolate y for equations with addition/subtraction and multiplication

For equations of the form $ay + c = d$ or $ay - c = d$, first perform inverse - operation for addition/subtraction. For $5y+15 = 65$, subtract 15 from both sides: $5y=65 - 15$, then divide by 5. 1.

Given $3y = 27$, then $y=\frac{27}{3}=9$.

Given $9y = 81$, then $y=\frac{81}{9}=9$.

Given $12y = 132$, then $y=\frac{132}{12}=11$.

Given $6y = 72$, then $y=\frac{72}{6}=12$.

Given $20y = 120$, then $y=\frac{120}{20}=6$.

Given $15y = 75$, then $y=\frac{75}{15}=5$.

Given $10y = 160$, then $y=\frac{160}{10}=16$.

Given $9y = 72$, then $y=\frac{72}{9}=8$.

Given $11y = 88$, then $y=\frac{88}{11}=8$.

Given $4y = 36$, then $y=\frac{36}{4}=9$.

Given $5y + 15 = 65$, first subtract 15 from both sides: $5y=65 - 15 = 50$, then $y=\frac{50}{5}=10$.

Given $9y + 20 = 83$, first subtract 20 from both sides: $9y=83 - 20 = 63$, then $y=\frac{63}{9}=7$.

Given $7y + 9 = 44$, first subtract 9 from both sides: $7y=44 - 9 = 35$, then $y=\frac{35}{7}=5$.

Given $4y + 18 = 34$, first subtract 18 from both sides: $4y=34 - 18 = 16$, then $y=\frac{16}{4}=4$.

Given $6y + 40 = 100$, first subtract 40 from both sides: $6y=100 - 40 = 60$, then $y=\frac{60}{6}=10$.

Given $12y-15 = 45$, first add 15 to both sides: $12y=45 + 15 = 60$, then $y=\frac{60}{12}=5$.

Given $8y-22 = 42$, first add 22 to both sides: $8y=42 + 22 = 64$, then $y=\frac{64}{8}=8$.

Given $5y-8 = 27$, first add 8 to both sides: $5y=27 + 8 = 35$, then $y=\frac{35}{5}=7$.

Given $11y-13 = 53$, first add 13 to both sides: $11y=53 + 13 = 66$, then $y=\frac{66}{11}=6$.

Given $3y-24 = 0$, first add 24 to both sides: $3y=24$, then $y=\frac{24}{3}=8$.

Answer:

$y = 9$
$y = 9$
$y = 11$
$y = 12$
$y = 6$
$y = 5$
$y = 16$
$y = 8$
$y = 8$
$y = 9$
$y = 10$
$y = 7$
$y = 5$
$y = 4$
$y = 10$
$y = 5$
$y = 8$
$y = 7$
$y = 6$
$y = 8$