alices backyard is a rectangular piece of property that is twice as long as it is wide. the total area of…

alices backyard is a rectangular piece of property that is twice as long as it is wide. the total area of her yard is 1,000 m². what is the approximate width of her backyard?\n$a = lw$\n11.2 m\n15.8 m\n22.4 m\n44.8 m

alices backyard is a rectangular piece of property that is twice as long as it is wide. the total area of her yard is 1,000 m². what is the approximate width of her backyard?\n$a = lw$\n11.2 m\n15.8 m\n22.4 m\n44.8 m

Answer

Explanation:

Step1: Define variables

Let the width be $w$ meters. Then the length $l = 2w$ meters.

Step2: Use area formula

The area formula for a rectangle is $A=lw$. Substitute $l = 2w$ and $A = 1000$ into the formula: $1000=(2w)w=2w^{2}$.

Step3: Solve for $w$

First, divide both sides of the equation $2w^{2}=1000$ by 2: $w^{2}=500$. Then take the square - root of both sides: $w=\sqrt{500}\approx22.4$ (since width cannot be negative and $\sqrt{500}\approx22.36$).

Answer:

C. 22.4 m