amira is solving the equation $x^{2}-6x = 1$. which value must be added to both sides of the equation to…

amira is solving the equation $x^{2}-6x = 1$. which value must be added to both sides of the equation to make the left side a perfect - square trinomial?\n-9\n8\n9\n36

amira is solving the equation $x^{2}-6x = 1$. which value must be added to both sides of the equation to make the left side a perfect - square trinomial?\n-9\n8\n9\n36

Answer

Explanation:

Step1: Recall the formula for perfect - square trinomial

For a quadratic expression of the form (x^{2}+bx), to make it a perfect - square trinomial, we add ((\frac{b}{2})^{2}). In the given equation (x^{2}-6x = 1), here (b=-6).

Step2: Calculate the value to be added

Substitute (b = - 6) into ((\frac{b}{2})^{2}). We have (\left(\frac{-6}{2}\right)^{2}=(-3)^{2}=9).

Answer:

C. 9