anya found the slope of the line that passes through the points (-7, 4) and (2, -3). her work is shown…

anya found the slope of the line that passes through the points (-7, 4) and (2, -3). her work is shown below. let (x2, y2) be (-7, 4) and (x1, y1) be (2, -3). m = \\frac{x2 - x1}{y2 - y1}=\\frac{-7 - 2}{4 - (-3)}=-\\frac{9}{7}. the slope is -\\frac{9}{7}. what error did she make? she simplified the denominator incorrectly. the denominator simplifies to -7. she labeled the points incorrectly. the point (-7, 4) should be (x1, y1). she used an incorrect formula. the formula should be the change in y - values with respect to the change in the x - values. she used an incorrect formula. the formula should be the sum of the x - values with respect to the sum of the y - values.

anya found the slope of the line that passes through the points (-7, 4) and (2, -3). her work is shown below. let (x2, y2) be (-7, 4) and (x1, y1) be (2, -3). m = \\frac{x2 - x1}{y2 - y1}=\\frac{-7 - 2}{4 - (-3)}=-\\frac{9}{7}. the slope is -\\frac{9}{7}. what error did she make? she simplified the denominator incorrectly. the denominator simplifies to -7. she labeled the points incorrectly. the point (-7, 4) should be (x1, y1). she used an incorrect formula. the formula should be the change in y - values with respect to the change in the x - values. she used an incorrect formula. the formula should be the sum of the x - values with respect to the sum of the y - values.

Answer

Explanation:

Step1: Recall slope - formula

The slope $m$ of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by $m=\frac{y_2 - y_1}{x_2 - x_1}$, which represents the change in $y$ - values with respect to the change in $x$ - values.

Step2: Analyze Anya's work

Anya used the formula $m=\frac{x_2 - x_1}{y_2 - y_1}$, which is incorrect. The correct formula should be the change in $y$ - values with respect to the change in $x$ - values.

Answer:

She used an incorrect formula. The formula should be the change in $y$-values with respect to the change in the $x$-values.