apples cost $2 each and oranges cost $3 each. a fruit stand has $60 to spend on buying apples and oranges…

apples cost $2 each and oranges cost $3 each. a fruit stand has $60 to spend on buying apples and oranges. an equation representing the total cost is 2x + 3y = 60, where x is the number of apples and y is the number of oranges. if the stand wants to buy 12 apples, what is the maximum number of oranges they can buy while staying within the $60 budget?

apples cost $2 each and oranges cost $3 each. a fruit stand has $60 to spend on buying apples and oranges. an equation representing the total cost is 2x + 3y = 60, where x is the number of apples and y is the number of oranges. if the stand wants to buy 12 apples, what is the maximum number of oranges they can buy while staying within the $60 budget?

Answer

Explanation:

Step1: Substitute (x = 12) into the equation

Given the equation (2x+3y = 60), when (x = 12), we have (2\times12+3y=60).

Step2: Simplify the left - hand side

(24 + 3y=60).

Step3: Solve for (y)

Subtract 24 from both sides: (3y=60 - 24), so (3y = 36). Then divide both sides by 3: (y=\frac{36}{3}).

Answer:

(12)