what is the approximate value of $log_{6}25$?\n0.233\n0.557\n0.620\n1.796

what is the approximate value of $log_{6}25$?\n0.233\n0.557\n0.620\n1.796

what is the approximate value of $log_{6}25$?\n0.233\n0.557\n0.620\n1.796

Answer

Explanation:

Step1: Aplicar la fórmula de cambio de base

$\log_{a}b=\frac{\ln b}{\ln a}$, entonces $\log_{6}25 = \frac{\ln 25}{\ln 6}$.

Step2: Calcular los valores de los logaritmos naturales

$\ln 25\approx3.218876$ y $\ln 6\approx1.791759$.

Step3: Realizar la división

$\frac{\ln 25}{\ln 6}\approx\frac{3.218876}{1.791759}\approx1.796$.

Answer:

D. 1.796