what is the area of this figure?\nprovide an answer accurate to the nearest tenth. use 3.14 or a calculator…

Explanation:

Step1: Calculate area of top parallelogram

Area of parallelogram = base × height $A_1 = 4 \times 5 = 20$ sq ft

Step2: Calculate area of right rectangle

Area of rectangle = length × width $A_2 = 8 \times 4 = 32$ sq ft

Step3: Calculate area of left vertical rectangle

$A_3 = 2 \times 7 = 14$ sq ft

Step4: Calculate area of middle lower rectangle

First find its height: $7 - 3 = 4$ ft $A_4 = 5 \times 4 = 20$ sq ft

Step5: Calculate area of middle trapezoid

Trapezoid area = $\frac{1}{2} \times (a + b) \times h$, where $a=2$ ft, $b=1$ ft, $h=5$ ft $A_5 = \frac{1}{2} \times (2 + 1) \times 5 = 7.5$ sq ft

Step6: Sum all individual areas

Total area $A = A_1 + A_2 + A_3 + A_4 + A_5$ $A = 20 + 32 + 14 + 20 + 7.5$

Answer:

93.5 square feet