what is the area of this figure?\nwrite your answer using decimals, if necessary.\nsquare feet

Explanation:

Step1: Divide the figure into simpler shapes

Divide the figure into a left rectangle, a right rectangle, and a bottom triangle.

Step2: Calculate the area of the left rectangle

The left rectangle has a width of $3\text{ ft}$ and a height of $6\text{ ft}$. $$A_{1} = 3 \times 6 = 18\text{ ft}^{2}$$

Step3: Calculate the area of the right rectangle

The right rectangle has a width of $2\text{ ft}$ and a height of $8\text{ ft}$. $$A_{2} = 2 \times 8 = 16\text{ ft}^{2}$$

Step4: Calculate the area of the bottom triangle

The triangle has a base of $2\text{ ft}$ and a height of $6\text{ ft}$. $$A_{3} = \frac{1}{2} \times 2 \times 6 = 6\text{ ft}^{2}$$

Step5: Sum the areas of all parts

Add the areas of the two rectangles and the triangle. $$A_{total} = 18 + 16 + 6 = 40\text{ ft}^{2}$$

Answer:

40 square feet