what is the area of parallelogram abcd?\n13 square units\n14 square units\n15 square units\n16 square units

what is the area of parallelogram abcd?\n13 square units\n14 square units\n15 square units\n16 square units

what is the area of parallelogram abcd?\n13 square units\n14 square units\n15 square units\n16 square units

Answer

Explanation:

Step1: Identify coordinates of vertices

Assume coordinates from the grid:
D(2,2), A(3,6), B(6,5), C(5,1) (adjusted from grid intersections).

Step2: Calculate base and height or use vector method

Use vector cross-product for area. Vectors:
$\overrightarrow{AD} = (3-2, 6-2) = (1,4)$,
$\overrightarrow{AB} = (6-3, 5-6) = (3,-1)$.
Area = $|1(-1) - 4(3)| = |-1 - 12| = 13$.

Answer:

A. 13 square units