how do the areas of the parallelograms compare? the area of parallelogram abcd is 4 square units greater…

Explanation:

Step1: Recall area formula

The area formula of a parallelogram is $A = base\times height$.

Step2: Find base and height of parallelogram ABCD

For parallelogram ABCD, the base along the x - axis from $x = 2$ to $x = 6$ has length $b_{1}=4$, and the height from $y = 2$ to $y = 6$ is $h_{1}=4$. So $A_{1}=b_{1}\times h_{1}=4\times4 = 16$ square units.

Step3: Find base and height of parallelogram EFGH

For parallelogram EFGH, the base along the x - axis from $x=-5$ to $x = - 1$ has length $b_{2}=4$, and the height from $y = 2$ to $y = 6$ is $h_{2}=4$. So $A_{2}=b_{2}\times h_{2}=4\times4=16$ square units.

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.