an arithmetic sequence has the the terms t(1) = 9 and t(4) = 24.write the equation for the sequence.hint…

an arithmetic sequence has the the terms t(1) = 9 and t(4) = 24.write the equation for the sequence.hint : find the constant difference (slope), then use it to find term 0.t(n) =
Answer
Explanation:
Step1: Find constant difference $d$
Recall arithmetic sequence formula $t(n) = t(1) + (n-1)d$. Substitute $t(1)=9$, $t(4)=24$, $n=4$: $$24 = 9 + (4-1)d$$ $$24 - 9 = 3d$$ $$15 = 3d$$ $$d = \frac{15}{3} = 5$$
Step2: Find $t(0)$ (term 0)
Use $t(0) = t(1) - d$: $$t(0) = 9 - 5 = 4$$
Step3: Write sequence equation
General form: $t(n) = t(0) + nd$. Substitute $t(0)=4$, $d=5$: $$t(n) = 4 + 5n$$
Answer:
Equation for the sequence: $\boldsymbol{t(n) = 5n + 4}$ Term 0: $\boldsymbol{4}$