what is the axis of symmetry of $h(x)=-2x^{2}+12x - 3$?\n$x=-15$\n$x=-3$\n$x = 3$\n$x=15$
what is the axis of symmetry of $h(x)=-2x^{2}+12x - 3$?\n$x=-15$\n$x=-3$\n$x = 3$\n$x=15$
Answer
Explanation:
Step1: Identify coefficients
For a quadratic function $y = ax^{2}+bx + c$, in $h(x)=-2x^{2}+12x - 3$, $a=-2$, $b = 12$, $c=-3$.
Step2: Use axis - of - symmetry formula
The formula for the axis of symmetry of a quadratic function is $x=-\frac{b}{2a}$. Substitute $a=-2$ and $b = 12$ into the formula: $x=-\frac{12}{2\times(-2)}$.
Step3: Calculate the value
$x=-\frac{12}{-4}=3$.
Answer:
C. $x = 3$