what is the axis of symmetry of the function f(x)=-(x + 9)(x - 21)?\no x=-15\no x=-6\no x=6\no x=15

what is the axis of symmetry of the function f(x)=-(x + 9)(x - 21)?\no x=-15\no x=-6\no x=6\no x=15
Answer
Explanation:
Step1: Identify the x - intercepts
The x - intercepts of the function $f(x)=-(x + 9)(x - 21)$ are found by setting $f(x)=0$. So $x+9 = 0$ gives $x=-9$ and $x - 21=0$ gives $x = 21$.
Step2: Use the axis - of - symmetry formula
The axis of symmetry of a quadratic function in factored form $y=a(x - p)(x - q)$ is $x=\frac{p + q}{2}$. Here $p=-9$ and $q = 21$. Then $x=\frac{-9+21}{2}$.
Step3: Calculate the value of x
$\frac{-9 + 21}{2}=\frac{12}{2}=6$.
Answer:
C. $x = 6$