what is the axis of symmetry and vertex for the function $f(x)=3(x - 2)^2+4$?\n$x = square$\nvertex…
what is the axis of symmetry and vertex for the function $f(x)=3(x - 2)^2+4$?\n$x = square$\nvertex: $(square,square)$
Answer
Explanation:
Step1: Recall vertex - form of quadratic function
The vertex - form of a quadratic function is $y = a(x - h)^2+k$, where $(h,k)$ is the vertex and the axis of symmetry is $x = h$.
Step2: Identify values of h and k
For the function $f(x)=3(x - 2)^2+4$, we have $h = 2$ and $k = 4$.
Answer:
$x = 2$ Vertex: $(2,4)$