blake knows that one of the solutions to $x^{2}-6x + 8 = 0$ is $x = 2$. what is the other solution?\n$x=-6$\n…

blake knows that one of the solutions to $x^{2}-6x + 8 = 0$ is $x = 2$. what is the other solution?\n$x=-6$\n$x=-3$\n$x = 4$\n$x = 8$

blake knows that one of the solutions to $x^{2}-6x + 8 = 0$ is $x = 2$. what is the other solution?\n$x=-6$\n$x=-3$\n$x = 4$\n$x = 8$

Answer

Explanation:

Step1: Factor the quadratic equation

For the quadratic equation (x^{2}-6x + 8=0), we factor it as ((x - 2)(x - 4)=0) since ((x - a)(x - b)=x^{2}-(a + b)x+ab) and here (a + b=6), (ab = 8) and one root is (x = 2) so the other factor gives the other root.

Step2: Find the other root

If ((x - 2)(x - 4)=0), then by the zero - product property, either (x-2=0) (which gives (x = 2)) or (x - 4=0). Solving (x - 4=0) gives (x=4).

Answer:

C. (x = 4)