brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a…

brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% copper, resulting in 100 pounds of brass that is 65% copper. which equation can be used to find x, the amount of 60% mixture used to create the 65% mixture? 0.8(100 - x)+0.6x = 100(0.65) 0.6(100 - x)+0.8x = 100(0.65) 0.8(100)+0.6x = 0.65(100 - x) 0.6(x)+0.8(100 + x)=0.65

brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% copper, resulting in 100 pounds of brass that is 65% copper. which equation can be used to find x, the amount of 60% mixture used to create the 65% mixture? 0.8(100 - x)+0.6x = 100(0.65) 0.6(100 - x)+0.8x = 100(0.65) 0.8(100)+0.6x = 0.65(100 - x) 0.6(x)+0.8(100 + x)=0.65

Answer

Explanation:

Step1: Define the amounts

Let $x$ be the amount of the 60% - copper mixture. Then the amount of the 80% - copper mixture is $100 - x$ (since the total amount of the final brass mixture is 100 pounds).

Step2: Calculate the copper - content in each part

The amount of copper in the 80% - copper mixture is $0.8(100 - x)$ (80% or 0.8 times the amount of the 80% - copper mixture). The amount of copper in the 60% - copper mixture is $0.6x$ (60% or 0.6 times the amount of the 60% - copper mixture). The amount of copper in the final 100 - pound, 65% - copper mixture is $100\times0.65$.

Step3: Set up the equation

The sum of the copper in the two initial mixtures equals the copper in the final mixture. So, $0.8(100 - x)+0.6x = 100\times0.65$.

Answer:

$0.8(100 - x)+0.6x = 100(0.65)$