3) a cattle train left miami and traveled toward new york. 14 hours later a diesel train left traveling at…

3) a cattle train left miami and traveled toward new york. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. after traveling for four hours the diesel train finally caught up. what was the cattle trains average speed?

3) a cattle train left miami and traveled toward new york. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. after traveling for four hours the diesel train finally caught up. what was the cattle trains average speed?

Answer

Explanation:

Step1: Calculate the distance the diesel train traveled

The diesel train's speed is 45 km/h and it traveled for 4 hours. Using the formula $d = vt$ (distance = speed×time), the distance $d$ it traveled is $d = 45\times4=180$ km.

Step2: Calculate the time the cattle train traveled

The cattle train started 14 hours earlier and the diesel - train traveled for 4 hours to catch up. So the cattle train traveled for $t_{cattle}=14 + 4=18$ hours.

Step3: Calculate the speed of the cattle train

Since the diesel train caught up with the cattle train, they traveled the same distance. Let the speed of the cattle train be $v_{cattle}$. We know the distance the cattle train traveled is also 180 km and it traveled for 18 hours. Using the formula $v=\frac{d}{t}$, we have $v_{cattle}=\frac{180}{18}=10$ km/h.

Answer:

10 km/h