3^{-2}cdot(7 - 4)^{2}+(7 + 4)^{2}
3^{-2}cdot(7 - 4)^{2}+(7 + 4)^{2}
Answer
Explanation:
Step1: Calculate values inside parentheses
$7 - 4=3$, $7 + 4 = 11$
Step2: Calculate exponents
$3^{-2}=\frac{1}{3^{2}}=\frac{1}{9}$, $(7 - 4)^{2}=3^{2}=9$, $(7 + 4)^{2}=11^{2}=121$
Step3: Perform multiplication
$3^{-2}\cdot(7 - 4)^{2}=\frac{1}{9}\times9 = 1$
Step4: Perform addition
$1+121=122$
Answer:
$122$