what is the center of a circle represented by the equation (x - 5)^2+(y + 6)^2=4^2?\n(-6,5)\n(-5,6)\n(5,-6)\n…

Explanation:

Step1: Recall circle - equation formula

The standard form of the equation of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Identify $h$ and $k$ values

Given the equation $(x - 5)^2+(y+6)^2 = 4^2$, we can rewrite $(y + 6)^2$ as $(y-(-6))^2$. Comparing with the standard - form $(x - h)^2+(y - k)^2=r^2$, we have $h = 5$ and $k=-6$.

Answer:

$(5,-6)$