what is the center of a circle represented by the equation $(x + 9)^2+(y - 6)^2=10^2$?\n(-9,6)\n(-6,9)\n(6,-9…
what is the center of a circle represented by the equation $(x + 9)^2+(y - 6)^2=10^2$?\n(-9,6)\n(-6,9)\n(6,-9)\n(9,-6)
Answer
Explanation:
Step1: Recall circle - equation formula
The standard form of a circle equation is $(x - a)^2+(y - b)^2=r^2$, where $(a,b)$ is the center of the circle and $r$ is the radius.
Step2: Rewrite the given equation
The given equation is $(x + 9)^2+(y - 6)^2=10^2$, which can be rewritten as $(x-(-9))^2+(y - 6)^2=10^2$.
Answer:
A. $(-9,6)$