chin was shown the graph of a line that contained point (1, 7). he wrote f(x)=4x + 3 to correctly represent…

chin was shown the graph of a line that contained point (1, 7). he wrote f(x)=4x + 3 to correctly represent the line. which of these equations could represent the same line?\no y - 7 = 3(x - 1)\no y - 1 = 3(x - 7)\no y - 7 = 4(x - 1)\no y - 1 = 4(x - 7)

chin was shown the graph of a line that contained point (1, 7). he wrote f(x)=4x + 3 to correctly represent the line. which of these equations could represent the same line?\no y - 7 = 3(x - 1)\no y - 1 = 3(x - 7)\no y - 7 = 4(x - 1)\no y - 1 = 4(x - 7)

Answer

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope. Given $f(x)=4x + 3$, the slope $m = 4$. The line passes through the point $(1,7)$, so $x_1 = 1$ and $y_1=7$.

Step2: Substitute values

Substituting $m = 4$, $x_1 = 1$ and $y_1 = 7$ into the point - slope form $y - y_1=m(x - x_1)$, we get $y - 7=4(x - 1)$.

Answer:

$y - 7=4(x - 1)$