choose the expression that shows the correct product for $sqrt{3}cdotsqrt{12}$\n$sqrt{15}$\n$sqrt{36}$\n$sqrt…
choose the expression that shows the correct product for $sqrt{3}cdotsqrt{12}$\n$sqrt{15}$\n$sqrt{36}$\n$sqrt4{15}$\n$sqrt4{36}$\ndone
Answer
Explanation:
Step1: Recall square - root product rule
$\sqrt{a}\cdot\sqrt{b}=\sqrt{a\cdot b}$ (where $a\geq0$ and $b\geq0$). For $\sqrt{3}\cdot\sqrt{12}$, we have $a = 3$ and $b = 12$.
Step2: Calculate the product inside the square - root
$a\cdot b=3\times12 = 36$. So $\sqrt{3}\cdot\sqrt{12}=\sqrt{3\times12}=\sqrt{36}$.
Answer:
$\sqrt{36}$