choose the sum that is greater than 5.\n$4\\frac{1}{8}+\\frac{5}{8}$ $4\\frac{3}{8}+\\frac{3}{8}$…

choose the sum that is greater than 5.\n$4\\frac{1}{8}+\\frac{5}{8}$ $4\\frac{3}{8}+\\frac{3}{8}$ $4\\frac{5}{8}+\\frac{7}{8}$ $4\\frac{6}{8}+\\frac{1}{8}$

choose the sum that is greater than 5.\n$4\\frac{1}{8}+\\frac{5}{8}$ $4\\frac{3}{8}+\\frac{3}{8}$ $4\\frac{5}{8}+\\frac{7}{8}$ $4\\frac{6}{8}+\\frac{1}{8}$

Answer

Explanation:

Step1: Convert mixed - numbers to improper fractions

$4\frac{1}{8}=\frac{4\times8 + 1}{8}=\frac{33}{8}$, $4\frac{3}{8}=\frac{4\times8+3}{8}=\frac{35}{8}$, $4\frac{5}{8}=\frac{4\times8 + 5}{8}=\frac{37}{8}$, $4\frac{6}{8}=\frac{4\times8+6}{8}=\frac{38}{8}$

Step2: Calculate each sum

  • For $4\frac{1}{8}+\frac{5}{8}=\frac{33}{8}+\frac{5}{8}=\frac{33 + 5}{8}=\frac{38}{8}=4.75$
  • For $4\frac{3}{8}+\frac{3}{8}=\frac{35}{8}+\frac{3}{8}=\frac{35 + 3}{8}=\frac{38}{8}=4.75$
  • For $4\frac{5}{8}+\frac{7}{8}=\frac{37}{8}+\frac{7}{8}=\frac{37+7}{8}=\frac{44}{8}=5.5$
  • For $4\frac{6}{8}+\frac{1}{8}=\frac{38}{8}+\frac{1}{8}=\frac{38 + 1}{8}=\frac{39}{8}=4.875$

Step3: Compare with 5

We see that $\frac{44}{8}=5.5>5$

Answer:

$4\frac{5}{8}+\frac{7}{8}$