combine these radicals.\n$sqrt{27}-sqrt{3}$\n$sqrt{24}$\n$2sqrt{3}$\n$-2sqrt{3}$\n$-3sqrt{2}$
combine these radicals.\n$sqrt{27}-sqrt{3}$\n$sqrt{24}$\n$2sqrt{3}$\n$-2sqrt{3}$\n$-3sqrt{2}$
Answer
Explanation:
Step1: Simplify $\sqrt{27}$
We know that $27 = 9\times3$, so $\sqrt{27}=\sqrt{9\times3}=\sqrt{9}\times\sqrt{3}=3\sqrt{3}$.
Step2: Subtract $\sqrt{3}$
Substitute $\sqrt{27}=3\sqrt{3}$ into the original expression: $3\sqrt{3}-\sqrt{3}=(3 - 1)\sqrt{3}=2\sqrt{3}$.
Answer:
B. $2\sqrt{3}$