complete the equation of the line through (-10,3) and (-8,-8). use exact numbers. y =

Explanation:

Step1: Calculate the slope

The slope $m$ of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by $m=\frac{y_2 - y_1}{x_2 - x_1}$. Here, $x_1=-10,y_1 = 3,x_2=-8,y_2=-8$. So $m=\frac{-8 - 3}{-8-(-10)}=\frac{-11}{2}=-\frac{11}{2}$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$. Using the point $(-10,3)$ and $m =-\frac{11}{2}$, we have $y - 3=-\frac{11}{2}(x+10)$.

Step3: Convert to slope - intercept form

Expand the right - hand side: $y - 3=-\frac{11}{2}x-55$. Then add 3 to both sides to get $y=-\frac{11}{2}x-52$.

Answer:

$y =-\frac{11}{2}x - 52$