what is the completely factored form of 12xy - 9x - 8y + 6?\n(3x - 2)(4y - 3)\n3x(4y - 3) - 2(4y +…

what is the completely factored form of 12xy - 9x - 8y + 6?\n(3x - 2)(4y - 3)\n3x(4y - 3) - 2(4y + 3)\n-6x(4y - 3)(4y - 3)\n(3x - 2)(4y - 3)(4y - 3)

what is the completely factored form of 12xy - 9x - 8y + 6?\n(3x - 2)(4y - 3)\n3x(4y - 3) - 2(4y + 3)\n-6x(4y - 3)(4y - 3)\n(3x - 2)(4y - 3)(4y - 3)

Answer

Explanation:

Step1: Group the terms

Group the first - two terms and the last two terms: $(12xy - 9x)+(-8y + 6)$

Step2: Factor out the greatest common factor from each group

From the first group $12xy - 9x$, the GCF is $3x$, so $12xy - 9x=3x(4y - 3)$. From the second group $-8y + 6$, the GCF is $-2$, so $-8y + 6=-2(4y - 3)$. Then the expression becomes $3x(4y - 3)-2(4y - 3)$.

Step3: Factor out the common binomial factor

Factor out the common binomial factor $(4y - 3)$: $(3x - 2)(4y - 3)$

Answer:

$(3x - 2)(4y - 3)$