what is the completely factored form of $6x^{2}-13x - 5$?\n(2x - 5)(3x + 1)\n(2x + 5)(3x - 1)\n(2x - 1)(3x…

what is the completely factored form of $6x^{2}-13x - 5$?\n(2x - 5)(3x + 1)\n(2x + 5)(3x - 1)\n(2x - 1)(3x - 5)\n(2x + 1)(3x + 5)

what is the completely factored form of $6x^{2}-13x - 5$?\n(2x - 5)(3x + 1)\n(2x + 5)(3x - 1)\n(2x - 1)(3x - 5)\n(2x + 1)(3x + 5)

Answer

Explanation:

Step1: Use FOIL method check

For option A: $(2x - 5)(3x+1)=2x\times3x+2x\times1-5\times3x - 5\times1=6x^{2}+2x - 15x-5=6x^{2}-13x - 5$.

Step2: Check other options

For option B: $(2x + 5)(3x - 1)=6x^{2}-2x+15x - 5=6x^{2}+13x - 5$. For option C: $(2x - 1)(3x - 5)=6x^{2}-10x-3x + 5=6x^{2}-13x + 5$. For option D: $(2x + 1)(3x + 5)=6x^{2}+10x+3x+5=6x^{2}+13x + 5$.

Answer:

A. $(2x - 5)(3x + 1)$