what is the completely factored form of $xy^{3}-x^{3}y$?\n$xy(y + x)(y - x)$\n$xy(y - x)(y - x)$\n$xy(x…

what is the completely factored form of $xy^{3}-x^{3}y$?\n$xy(y + x)(y - x)$\n$xy(y - x)(y - x)$\n$xy(x - y)(x^{2}+xy + y^{2})$\n$xy(x - y)(y^{2}+xy + x^{2})$

what is the completely factored form of $xy^{3}-x^{3}y$?\n$xy(y + x)(y - x)$\n$xy(y - x)(y - x)$\n$xy(x - y)(x^{2}+xy + y^{2})$\n$xy(x - y)(y^{2}+xy + x^{2})$

Answer

Explanation:

Step1: Factor out the common factor

First, factor out the common factor $xy$ from $xy^{3}-x^{3}y$. We get $xy(y^{2}-x^{2})$.

Step2: Use the difference - of - squares formula

Recall the difference - of - squares formula $a^{2}-b^{2}=(a + b)(a - b)$. Here $a = y$ and $b=x$, so $y^{2}-x^{2}=(y + x)(y - x)$.

Answer:

A. $xy(y + x)(y - x)$