the concession stand at the local high school sells pretzels and lemonade. the total cost of two pretzels…

the concession stand at the local high school sells pretzels and lemonade. the total cost of two pretzels and a lemonade is $5.75. the total cost of two lemonades is $0.25 more than the cost of a pretzel. what is the cost of a pretzel?\n$1.25\n$2.00\n$2.25\n$2.75

the concession stand at the local high school sells pretzels and lemonade. the total cost of two pretzels and a lemonade is $5.75. the total cost of two lemonades is $0.25 more than the cost of a pretzel. what is the cost of a pretzel?\n$1.25\n$2.00\n$2.25\n$2.75

Answer

Explanation:

Step1: Define variables

Let $p$ be the cost of a pretzel and $l$ be the cost of a lemon - ade. We have the equations: $2p + l=5.75$ and $2l=p + 0.25$.

Step2: Solve the second equation for $l$

From $2l=p + 0.25$, we get $l=\frac{p + 0.25}{2}$.

Step3: Substitute $l$ into the first equation

Substitute $l=\frac{p + 0.25}{2}$ into $2p + l=5.75$. $2p+\frac{p + 0.25}{2}=5.75$. Multiply through by 2 to clear the fraction: $4p+(p + 0.25)=11.5$.

Step4: Simplify and solve for $p$

Expand: $4p + p+0.25 = 11.5$. Combine like - terms: $5p+0.25 = 11.5$. Subtract 0.25 from both sides: $5p=11.5 - 0.25=11.25$. Divide both sides by 5: $p=\frac{11.25}{5}=2.25$.

Answer:

C. $2.25$