condense the expression. log5 - 2logx log ?

Explanation:

Step1: Apply power - rule of logarithms

Recall that $n\log_aM=\log_aM^n$. So, $2\log x = \log x^2$. The expression becomes $\log5-\log x^2$.

Step2: Apply quotient - rule of logarithms

Recall that $\log_aM-\log_aN=\log_a\frac{M}{N}$. Here, $M = 5$ and $N=x^2$, so $\log5-\log x^2=\log\frac{5}{x^2}$.

Answer:

$\log\frac{5}{x^2}$