there are 4 consecutive odd integers with a sum of 64. what is the least of these integers?

Explanation:

Step1: Define the least integer as ( x )

Let the least odd integer be ( x ).

Step2: Express consecutive odd integers

Next three: ( x+2 ), ( x+4 ), ( x+6 ).

Step3: Set up sum equation

( x + (x+2) + (x+4) + (x+6) = 64 )

Step4: Simplify left side

( 4x + 12 = 64 )

Step5: Solve for ( x )

( 4x = 52 \Rightarrow x = 13 )

Answer:

13