consider circle t with radius 24 in. and $\theta=\frac{5pi}{6}$ radians. what is the length of minor arc sv…

consider circle t with radius 24 in. and $\theta=\frac{5pi}{6}$ radians. what is the length of minor arc sv? 20$pi$ in. 28$pi$ in. 40$pi$ in. 63$pi$ in.

consider circle t with radius 24 in. and $\theta=\frac{5pi}{6}$ radians. what is the length of minor arc sv? 20$pi$ in. 28$pi$ in. 40$pi$ in. 63$pi$ in.

Answer

Explanation:

Step1: Recall arc - length formula

The formula for the length of an arc of a circle is $s = r\theta$, where $s$ is the arc - length, $r$ is the radius of the circle, and $\theta$ is the central angle in radians.

Step2: Substitute given values

We are given that $r = 24$ inches and $\theta=\frac{5\pi}{6}$ radians. Substitute these values into the formula: $s=24\times\frac{5\pi}{6}$.

Step3: Simplify the expression

First, calculate $24\times\frac{5\pi}{6}=\frac{24\times5\pi}{6}$. Since $24\div6 = 4$, then $\frac{24\times5\pi}{6}=4\times5\pi = 20\pi$ inches.

Answer:

$20\pi$ in.