consider the expression $-6\\frac{3}{5}-(-7\\frac{4}{15})+2\\frac{1}{5}$. \na. estimate the value of the…

consider the expression $-6\\frac{3}{5}-(-7\\frac{4}{15})+2\\frac{1}{5}$. \na. estimate the value of the expression. show your work. \nb. find the exact value of the expression. show your work. \nc. use your estimate to explain if your answer to problem 4b is reasonable.

consider the expression $-6\\frac{3}{5}-(-7\\frac{4}{15})+2\\frac{1}{5}$. \na. estimate the value of the expression. show your work. \nb. find the exact value of the expression. show your work. \nc. use your estimate to explain if your answer to problem 4b is reasonable.

Answer

Explanation:

Step1: Estimate the value (for part a)

Round each mixed number to the nearest whole number. (-6\frac{3}{5}\approx - 7), (-(-7\frac{4}{15})\approx7), (2\frac{1}{5}\approx2) Then the expression (-7 + 7+2)

Step2: Calculate the exact value (for part b)

First, convert mixed numbers to improper fractions. (-6\frac{3}{5}=-\frac{6\times5 + 3}{5}=-\frac{33}{5}), (-(-7\frac{4}{15})=\frac{7\times15+4}{15}=\frac{109}{15}), (2\frac{1}{5}=\frac{2\times5 + 1}{5}=\frac{11}{5}) The expression becomes (-\frac{33}{5}+\frac{109}{15}+\frac{11}{5}) Combine the fractions with denominator 5: (\left(-\frac{33}{5}+\frac{11}{5}\right)+\frac{109}{15}=-\frac{22}{5}+\frac{109}{15}) Get a common denominator of 15: (-\frac{22\times3}{5\times3}+\frac{109}{15}=-\frac{66}{15}+\frac{109}{15}) Now, (\frac{-66 + 109}{15}=\frac{43}{15}=2\frac{13}{15})

Step3: Check reasonableness (for part c)

The estimate was (2) and the exact value is (2\frac{13}{15}\approx2.87). Since (2\frac{13}{15}) is close to the estimate of (2) (the difference between (2.87) and (2) is relatively small considering the rounding in the estimate), the exact answer is reasonable.

Answer:

a. Estimate: (2) (by rounding (-6\frac{3}{5}\approx - 7), (-(-7\frac{4}{15})\approx7), (2\frac{1}{5}\approx2) and calculating (-7 + 7+2)) b. Exact value: (\frac{43}{15}=2\frac{13}{15}) c. The exact value (2\frac{13}{15}\approx2.87) is close to the estimate of (2), so it is reasonable.