consider the function represented by the equation 6c = 2p - 10. write the equation in function notation…

consider the function represented by the equation 6c = 2p - 10. write the equation in function notation, where c is the independent variable.\n○ f(c)=\frac{1}{3}p+\frac{5}{3}\n○ f(c)=3c + 5\n○ f(p)=\frac{1}{3}p+\frac{5}{3}\n○ f(p)=3c + 5

consider the function represented by the equation 6c = 2p - 10. write the equation in function notation, where c is the independent variable.\n○ f(c)=\frac{1}{3}p+\frac{5}{3}\n○ f(c)=3c + 5\n○ f(p)=\frac{1}{3}p+\frac{5}{3}\n○ f(p)=3c + 5

Answer

Answer:

B. $f(c)=3c + 5$

Explanation:

Step1: Isolate $p$ in the given equation.

Starting with $6c = 2p-10$, add 10 to both sides: $6c + 10=2p$.

Step2: Solve for $p$.

Divide both sides by 2: $p=\frac{6c + 10}{2}=3c + 5$.

Step3: Write in function - notation.

Since $c$ is the independent variable, the function is $f(c)=3c + 5$.