consider the function represented by the equation 6q = 3s - 9. write the equation in function notation…

consider the function represented by the equation 6q = 3s - 9. write the equation in function notation, where q is the independent variable. f(q)=\frac{1}{2}q-\frac{3}{2} f(q)=2s + 3 f(s)=\frac{1}{2}s-\frac{3}{2} f(q)=2q + 3

consider the function represented by the equation 6q = 3s - 9. write the equation in function notation, where q is the independent variable. f(q)=\frac{1}{2}q-\frac{3}{2} f(q)=2s + 3 f(s)=\frac{1}{2}s-\frac{3}{2} f(q)=2q + 3

Answer

Explanation:

Step1: Isolate s

Starting with $6q = 3s - 9$, first add 9 to both sides: $6q+9 = 3s$.

Step2: Solve for s

Divide both sides of the equation $6q + 9=3s$ by 3. We get $s=\frac{6q + 9}{3}=2q + 3$.

Step3: Write in function - notation

Since q is the independent variable, we can write the function as $f(q)=2q + 3$.

Answer:

$f(q)=2q + 3$