consider the graph of the linear function $h(x)=-\frac{2}{3}x + 5$. which could you change to move the graph…

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a linear function is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. In the function $h(x)=-\frac{2}{3}x + 5$, $m =-\frac{2}{3}$ and $b = 5$.

Step2: Understand vertical shift

To move the graph of a linear function $y=mx + b$ down $k$ units, we subtract $k$ from the y - intercept $b$. Here, $k = 3$.

Step3: Calculate new y - intercept

The new y - intercept $b_{new}=b - k$. Substituting $b = 5$ and $k = 3$, we get $b_{new}=5 - 3=2$.

Answer:

the value of $b$ to $2$