consider the sets below.\nu = {x | x is a real number}\na = {x | x is an odd integer}\nr = {x | x = 3, 7…
consider the sets below.\nu = {x | x is a real number}\na = {x | x is an odd integer}\nr = {x | x = 3, 7, 11, 27}\nis r ⊂ a?\no yes, because all the elements of set a are in set r\no yes, because all the elements of set r are in set a\no no, because each element in set a is not represented in set r\no no, because each element in set r is not represented in set a
Answer
Explanation:
Step1: Check element - set relationship
Set (A) consists of odd integers. Set (R={3,7,11,27}). Each of (3,7,11,27) is an odd integer.
Step2: Recall subset definition
A set (R) is a subset of set (A) (denoted (R\subseteq A)) if every element of (R) is an element of (A). Since (3,7,11,27) are all in (A), (R\subseteq A).
Answer:
yes, because all the elements of set (R) are in set (A)