consider this system of equations. which shows the first equation written in slope - intercept…

consider this system of equations. which shows the first equation written in slope - intercept form?\n$\frac{1}{2}(2y + 10)=7x$\n$y = 8$\n$y=7x - 10$\n$y=\frac{7}{2}x - 5$\n$y=7x - 5$\n$y=\frac{7}{4}x - 5$

consider this system of equations. which shows the first equation written in slope - intercept form?\n$\frac{1}{2}(2y + 10)=7x$\n$y = 8$\n$y=7x - 10$\n$y=\frac{7}{2}x - 5$\n$y=7x - 5$\n$y=\frac{7}{4}x - 5$

Answer

Explanation:

Step1: Expand the left - hand side

$\frac{1}{2}(2y + 10)=y + 5$ So the equation becomes $y + 5=7x$.

Step2: Isolate y

Subtract 5 from both sides: $y=7x - 5$.

Answer:

$y = 7x-5$ (corresponding to the third option in the multiple - choice list)