a craftsperson must attach a lead strip around all four sides of a stained glass window that is…

a craftsperson must attach a lead strip around all four sides of a stained glass window that is $8\frac{3}{5}$ in. by $13\frac{21}{25}$ in. before it is installed. find the length of lead stripping needed.\nthe estimated length of lead stripping needed is \n(type a whole number.)

a craftsperson must attach a lead strip around all four sides of a stained glass window that is $8\frac{3}{5}$ in. by $13\frac{21}{25}$ in. before it is installed. find the length of lead stripping needed.\nthe estimated length of lead stripping needed is \n(type a whole number.)

Answer

Explanation:

Step1: Convert mixed - numbers to improper fractions

$8\frac{3}{5}=\frac{8\times5 + 3}{5}=\frac{43}{5}$ and $13\frac{21}{25}=\frac{13\times25+21}{25}=\frac{325 + 21}{25}=\frac{346}{25}$

Step2: Use the perimeter formula for a rectangle

The perimeter of a rectangle is $P = 2(l + w)$. Here, $l=\frac{346}{25}$ and $w=\frac{43}{5}$. First, make the common denominator for $l$ and $w$. $\frac{43}{5}=\frac{43\times5}{5\times5}=\frac{215}{25}$. Then $l + w=\frac{346}{25}+\frac{215}{25}=\frac{346 + 215}{25}=\frac{561}{25}$.

Step3: Calculate the perimeter

$P = 2\times\frac{561}{25}=\frac{1122}{25}=44.88$.

Step4: Round to a whole number

Rounding $44.88$ to a whole number gives $45$.

Answer:

$45$