a cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to…

a cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. what is the approximate volume of the tube? round to the nearest whole cubic centimeter. 1,005 cm³ 1,340 cm³ 3,351 cm³ 4,021 cm³

a cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. what is the approximate volume of the tube? round to the nearest whole cubic centimeter. 1,005 cm³ 1,340 cm³ 3,351 cm³ 4,021 cm³

Answer

Explanation:

Step1: Find the radius

The radius $r$ is half of the diameter. Given diameter $d = 8$ cm, so $r=\frac{d}{2}=\frac{8}{2}=4$ cm.

Step2: Use the volume - formula for a cylinder

The volume formula of a cylinder is $V=\pi r^{2}h$. Substitute $r = 4$ cm and $h = 20$ cm into the formula: $V=\pi\times4^{2}\times20=\pi\times16\times20 = 320\pi$ $cm^{3}$.

Step3: Approximate the value

Take $\pi\approx3.14$. Then $V\approx320\times3.14 = 1004.8$ $cm^{3}$. Rounding to the nearest whole - cubic centimeter, $V\approx1005$ $cm^{3}$.

Answer:

$1,005$ $cm^{3}$