dana is finding the perimeter of different - sized squares. she finds the perimeter is always 4 times longer…

dana is finding the perimeter of different - sized squares. she finds the perimeter is always 4 times longer than the side length. there is a proportional relationship between the side length of the square in inches, x, and the perimeter of the square in inches, y. graph this relationship. select two points to draw a line.

dana is finding the perimeter of different - sized squares. she finds the perimeter is always 4 times longer than the side length. there is a proportional relationship between the side length of the square in inches, x, and the perimeter of the square in inches, y. graph this relationship. select two points to draw a line.

Answer

Explanation:

Step1: Determine the relationship formula

The perimeter ( y ) of a square with side length ( x ) is given by ( y = 4x ) (since perimeter of square ( = 4\times ) side length).

Step2: Find two points

  • For ( x = 1 ): Substitute ( x = 1 ) into ( y = 4x ), we get ( y = 4\times1 = 4 ). So the point is ( (1, 4) ).
  • For ( x = 2 ): Substitute ( x = 2 ) into ( y = 4x ), we get ( y = 4\times2 = 8 ). So the point is ( (2, 8) ).

(We can also use ( x = 0 ), ( y = 0 ) as another point, but ( (1,4) ) and ( (2,8) ) are easy to plot.)

To graph, plot the points ( (1, 4) ) and ( (2, 8) ) (or other points from the formula ( y = 4x )) and draw a straight line through them since it's a proportional relationship (linear with ( y - )intercept at 0).

Answer:

To graph the relationship ( y = 4x ), two points can be ( (1, 4) ) and ( (2, 8) ) (or other valid points from the formula, e.g., ( (0, 0) ), ( (3, 12) ) etc.). Plot these points on the given coordinate plane (with ( x ) as side length and ( y ) as perimeter) and draw a straight line through them.