z.8 describe linear and exponential growth and decay klf\nhow does $h(t) = 6^t$ change over the interval…

z.8 describe linear and exponential growth and decay klf\nhow does $h(t) = 6^t$ change over the interval from $t = 1$ to $t = 3$\n$h(t)$ increases by a factor of 6\n$h(t)$ decreases by a factor of 36\n$h(t)$ increases by 6%\n$h(t)$ increases by a factor of 36
Answer
Explanation:
Step1: Calculate h(1)
$h(1) = 6^1 = 6$
Step2: Calculate h(3)
$h(3) = 6^3 = 216$
Step3: Find growth factor
$\frac{h(3)}{h(1)} = \frac{216}{6} = 36$
Answer:
h(t) increases by a factor of 36