which describes the location of the sum of $left(-\frac{1}{8}\right)+left(-6\frac{3}{10}\right)$ on a number…

which describes the location of the sum of $left(-\frac{1}{8}\right)+left(-6\frac{3}{10}\right)$ on a number line?\n$6\frac{3}{10}$ units to the left of $\frac{1}{8}$\n$6\frac{3}{10}$ units to the right of $\frac{1}{8}$\n$6\frac{3}{10}$ units to the left of $-\frac{1}{8}$\n$6\frac{3}{10}$ units to the right of $-\frac{1}{8}$

which describes the location of the sum of $left(-\frac{1}{8}\right)+left(-6\frac{3}{10}\right)$ on a number line?\n$6\frac{3}{10}$ units to the left of $\frac{1}{8}$\n$6\frac{3}{10}$ units to the right of $\frac{1}{8}$\n$6\frac{3}{10}$ units to the left of $-\frac{1}{8}$\n$6\frac{3}{10}$ units to the right of $-\frac{1}{8}$

Answer

Explanation:

Step1: Recall number - line addition rule

Adding a negative number means moving to the left on the number - line. We have the sum (-\frac{1}{8}+(- 6\frac{3}{10})). This is equivalent to (-\frac{1}{8}-6\frac{3}{10}). Starting from (-\frac{1}{8}), when we subtract (6\frac{3}{10}), we move (6\frac{3}{10}) units to the left.

Answer:

6\frac{3}{10} units to the left of -\frac{1}{8}