determine the total number of roots of each polynomial function using the factored form.\n$f(x)=(x + 1)(x…

determine the total number of roots of each polynomial function using the factored form.\n$f(x)=(x + 1)(x - 3)(x - 4)$\n$f(x)=(x + 5)^3(x - 9)(x + 1)$\n$f(x)=(x - 6)^2(x + 2)^2$

determine the total number of roots of each polynomial function using the factored form.\n$f(x)=(x + 1)(x - 3)(x - 4)$\n$f(x)=(x + 5)^3(x - 9)(x + 1)$\n$f(x)=(x - 6)^2(x + 2)^2$

Answer

Explanation:

Step1: Recall root - counting rule

The number of roots of a polynomial in factored form $f(x)=(x - r_1)^{n_1}(x - r_2)^{n_2}\cdots(x - r_k)^{n_k}$ is the sum of the exponents $n_1 + n_2+\cdots + n_k$.

Step2: Analyze $f(x)=(x + 5)^3(x - 9)(x + 1)$

The exponents of the factors are 3, 1, and 1.

Step3: Calculate the number of roots

$3+1 + 1=5$.

Answer:

5