determining the axis of symmetry of quadratic functions\nwhich functions have an axis of symmetry of ( x =…

determining the axis of symmetry of quadratic functions\nwhich functions have an axis of symmetry of ( x = - 2 )? check all that apply.\n( square f(x)=x^{2}+4 x + 3 )\n( square f(x)=x^{2}-4 x - 5 )\n( square f(x)=x^{2}+6 x + 2 )\n( square f(x)=-2 x^{2}-8 x + 1 )\n( square f(x)=-2 x^{2}+8 x - 2 )

determining the axis of symmetry of quadratic functions\nwhich functions have an axis of symmetry of ( x = - 2 )? check all that apply.\n( square f(x)=x^{2}+4 x + 3 )\n( square f(x)=x^{2}-4 x - 5 )\n( square f(x)=x^{2}+6 x + 2 )\n( square f(x)=-2 x^{2}-8 x + 1 )\n( square f(x)=-2 x^{2}+8 x - 2 )

Answer

Explanation:

Step1: Recall the formula for the axis of symmetry

For a quadratic function (f(x)=ax^{2}+bx + c), the axis of symmetry is given by (x =-\frac{b}{2a}).

Step2: Analyze (f(x)=x^{2}+4x + 3)

Here (a = 1), (b=4). Then (x=-\frac{4}{2\times1}=- 2).

Step3: Analyze (f(x)=x^{2}-4x - 5)

Here (a = 1), (b=-4). Then (x=-\frac{-4}{2\times1}=2).

Step4: Analyze (f(x)=x^{2}+6x + 2)

Here (a = 1), (b = 6). Then (x=-\frac{6}{2\times1}=-3).

Step5: Analyze (f(x)=-2x^{2}-8x + 1)

Here (a=-2), (b=-8). Then (x=-\frac{-8}{2\times(-2)}=-2).

Step6: Analyze (f(x)=-2x^{2}+8x - 2)

Here (a=-2), (b = 8). Then (x=-\frac{8}{2\times(-2)}=2).

Answer:

(f(x)=x^{2}+4x + 3), (f(x)=-2x^{2}-8x + 1)