in the diagram, wz = √26. what is the perimeter of parallelogram wxyz? w(-2,4) x(2,4) z(-3,-1) y(1,-1) 2√26…

Explanation:

Step1: Find length of WX

Use distance formula for two - points $(x_1,y_1)$ and $(x_2,y_2)$ which is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. For $W(-2,4)$ and $X(2,4)$, $x_1=-2,y_1 = 4,x_2=2,y_2 = 4$. Then $WX=\sqrt{(2-(-2))^2+(4 - 4)^2}=\sqrt{(4)^2+0^2}=4$.

Step2: Recall property of parallelogram

In parallelogram $WXYZ$, $WZ = XY=\sqrt{26}$ and $WX=ZY = 4$.

Step3: Calculate perimeter

Perimeter $P$ of parallelogram is $P=2WZ + 2WX$. Substitute $WZ=\sqrt{26}$ and $WX = 4$ into the formula. $P=2\sqrt{26}+2\times4=2\sqrt{26}+8$.

Answer:

$2\sqrt{26}+8$ units