what is the difference?\n$\frac{x}{x^{2}+3x + 2}-\frac{1}{(x + 2)(x + 1)}$\n$\frac{x - 1}{6x+4}$\n$\frac{-1}{…

what is the difference?\n$\frac{x}{x^{2}+3x + 2}-\frac{1}{(x + 2)(x + 1)}$\n$\frac{x - 1}{6x+4}$\n$\frac{-1}{4x + 2}$\n$\frac{1}{x+2}$\n$\frac{x - 1}{x^{2}+3x + 2}$

what is the difference?\n$\frac{x}{x^{2}+3x + 2}-\frac{1}{(x + 2)(x + 1)}$\n$\frac{x - 1}{6x+4}$\n$\frac{-1}{4x + 2}$\n$\frac{1}{x+2}$\n$\frac{x - 1}{x^{2}+3x + 2}$

Answer

Explanation:

Step 1: Factor the first denominator

$x^2 + 3x + 2 = (x + 1)(x + 2)$

Step 2: Rewrite with common denominator

$\frac{x}{(x + 1)(x + 2)} - \frac{1}{(x + 2)(x + 1)} = \frac{x - 1}{(x + 1)(x + 2)}$

Answer:

$\frac{x - 1}{x^2 + 3x + 2}$