what is a difference of squares that has a factor of x + 8?\n$x^{2}-4$\n$x^{2}-16$\n$x^{2}-64$\n$x^{2}-256$
what is a difference of squares that has a factor of x + 8?\n$x^{2}-4$\n$x^{2}-16$\n$x^{2}-64$\n$x^{2}-256$
Answer
Explanation:
Step1: Recall difference - of - squares formula
The difference - of - squares formula is (a^{2}-b^{2}=(a + b)(a - b)).
Step2: Check each option
For (x^{2}-4=(x + 2)(x - 2)), it does not have a factor of (x + 8). For (x^{2}-16=(x + 4)(x - 4)), it does not have a factor of (x + 8). For (x^{2}-64=(x + 8)(x - 8)), it has a factor of (x + 8). For (x^{2}-256=(x + 16)(x - 16)), it does not have a factor of (x + 8).
Answer:
(x^{2}-64)