the digits of a two - digit number sum to 8. when the digits are reversed, the resulting number is 18 less…

the digits of a two - digit number sum to 8. when the digits are reversed, the resulting number is 18 less than the original number. what is the original number?\n26\n35\n53\n62

the digits of a two - digit number sum to 8. when the digits are reversed, the resulting number is 18 less than the original number. what is the original number?\n26\n35\n53\n62

Answer

Answer:

C. 53

Explanation:

Step1: Check sum of digits for each option

For 26: $2 + 6=8$; for 35: $3 + 5 = 8$; for 53: $5+3 = 8$; for 62: $6 + 2=8$. All satisfy sum - to - 8 condition.

Step2: Check reversed - number condition

For 26, reversed is 62, and $26+18 = 44\neq62$. For 35, reversed is 53, and $35 + 18=53$. For 53, reversed is 35, and $53-18 = 35$. For 62, reversed is 26, and $62-18 = 44\neq26$. So the original number is 53.