what is the domain of the function $y = sqrt{x}$?\n$-infty<x<infty$\n$0<x<infty$\n$0leq x<infty$\n$1leq…

what is the domain of the function $y = sqrt{x}$?\n$-infty<x<infty$\n$0<x<infty$\n$0leq x<infty$\n$1leq x<infty$

what is the domain of the function $y = sqrt{x}$?\n$-infty<x<infty$\n$0<x<infty$\n$0leq x<infty$\n$1leq x<infty$

Answer

Explanation:

Step1: Recall square - root property

The expression under square - root must be non - negative. For the function $y = \sqrt{x}$, we need $x\geq0$.

Answer:

$0\leq x<\infty$ (the third option)